Saturday 30 November 2013

Strategy for Testing Series


We now have several ways of testing a series for convergence or divergence; the problem
is to decide which test to use on which series. In this respect testing series is similar to integrating
functions. Again there are no hard and fast rules about which test to apply to a
given series, but you may find the following advice of some use.
It is not wise to apply a list of the tests in a specific order until one finally works. That
would be a waste of time and effort. Instead, as with integration, the main strategy is to
classify the series according to its form.
1. If the series is of the form , it is a -series, which we know to be convergent
if and divergent if .
2. If the series has the form or , it is a geometric series, which converges
if and diverges if . Some preliminary algebraic manipulation
may be required to bring the series into this form.
3. If the series has a form that is similar to a -series or a geometric series, then
one of the comparison tests should be considered. In particular, if is a rational
function or algebraic function of (involving roots of polynomials), then the
series should be compared with a -series. (The value of should be chosen as
in Section 8.3 by keeping only the highest powers of in the numerator and
denominator.) The comparison tests apply only to series with positive terms, but
if has some negative terms, then we can apply the Comparison Test to
and test for absolute convergence.
4. If you can see at a glance that , then the Test for Divergence
should be used.
5. If the series is of the form or , then the Alternating Series
Test is an obvious possibility.
6. Series that involve factorials or other products (including a constant raised to the
th power) are often conveniently tested using the Ratio Test. Bear in mind that
as for all -series and therefore all rational or algebraic
functions of . Thus, the Ratio Test should not be used for such series.
7. If , where is easily evaluated, then the Integral Test is effective
(assuming the hypotheses of this test are satisfied).

Friday 29 November 2013

Convergence Tests


Absolute Convergence
If the series sum (1..inf) |an| converges, then the series sum (1..inf) an also converges.
Alternating Series Test
If for all n, an is positive, non-increasing (i.e. 0 < an+1 <= an), and approaching zero, then the alternating series
sum (1..inf) (-1)n an   and   sum (1..inf) (-1)n-1 an
both converge.
If the alternating series converges, then the remainder RN = S - SN (where S is the exact sum of the infinite series and SN is the sum of the first N terms of the series) is bounded by |RN| <= aN+1

Deleting the first N Terms
If N is a positive integer, then the series
sum (1..inf) an and  inf  
sum (n=N+1..inf) an  
n=N+1
both converge or both diverge.

Direct Comparison Test
If 0 <= an <= bn for all n greater than some positive integer N, then the following rules apply:
If sum (1..inf) bn converges, then sum (1..inf) an converges.
If sum (1..inf) an diverges, then sum (1..inf) bn diverges.

Geometric Series Convergence
The geometric series is given by
sum (n=0..inf) a rn = a + a r + a r2 + a r3 + ...
If |r| < 1 then the following geometric series converges to a / (1 - r).
If |r| >= 1 then the above geometric series diverges.


Integral Test
If for all n >= 1, f(n) = an, and f is positive, continuous, and decreasing then  
sum (1..inf) an and integral(1..inf) an 
either both converge or both diverge.
If the above series converges, then the remainder RN = S - SN (where S is the exact sum of the infinite series and SN is the sum of the first N terms of the series) is bounded by 0< = RN <= integral(N..inf) f(x) dx.
Limit Comparison Test
If lim (n-->inf) (an / bn) = L,
where an, bn > 0 and L is finite and positive,
then the series sum (1..inf) an and sum (1..inf) bn either both converge or both diverge.

nth-Term Test for Divergence

If the sequence {an} does not converge to zero, then the series sum (1..inf) andiverges.

p-Series Convergence
The p-series is given by
sum (1..inf) 1/np = 1/1p + 1/2p + 1/3p + ...
where p > 0 by definition.
If p > 1, then the series converges.
If 0 < p <= 1 then the series diverges.
Ratio Test
If for all n, n not equals 0, then the following rules apply:
Let L = lim (n -- > inf) | an+1 / an |.
If L < 1, then the series sum (1..inf) an converges.
If L > 1, then the series sum (1..inf) an diverges.
If L = 1, then the test in inconclusive.
Root Test
Let L = lim (n -- > inf) | an |1/n.
If L < 1, then the series sum (1..inf) an converges.
If L > 1, then the series sum (1..inf) an diverges.
If L = 1, then the test in inconclusive.
Taylor Series Convergence
If f has derivatives of all orders in an interval I centered at c, then the Taylor series converges as indicated:
sum (0..inf) (1/n!) f(n)(c) (x - c)n = f(x)
if and only if lim (n-->inf) RN = 0 for all x in I.
The remainder RN = S - SN of the Taylor series (where S is the exact sum of the infinite series and SN is the sum of the first N terms of the series) is equal to (1/(n+1)!) f(n+1)(z) (x - c)n+1, where z is some constant between x and c.


Reference: Math.Com@ http://www.math.com/tables/expansion/tests.htm

Thursday 24 October 2013

L-R Paulzy......
November 10th.
My birthday approaches.....



Monday 3 June 2013

Birthday Celebration_Ekemini Inyang

Ekemini Inyang is a year old today.
She is a kind, humble, cool girl.
I pray for long life and prosperity for her and her family.
WULLUP_HAPPY BIRTHDAY

wish ekemini b.o.d_follow this link: http://www.facebook.com/events/196813060470416/

Wednesday 10 April 2013

Great Thinker

"Pride shoots a personality upward without minding the law of gravitation"_ Mmemek-Abasi Paul